Integrand size = 26, antiderivative size = 178 \[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=-\frac {9}{32} e^{a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x^2 \left (c x^n\right )^{\left .-\frac {2}{3}\right /n}+\frac {9}{64} e^{-a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x^2 \left (c x^n\right )^{\left .\frac {2}{3}\right /n}-\frac {1}{32} e^{-3 a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x^2 \left (c x^n\right )^{2/n}+\frac {1}{8} e^{3 a \sqrt {-\frac {1}{n^2}} n} \sqrt {-\frac {1}{n^2}} n x^2 \left (c x^n\right )^{-2/n} \log (x) \]
-9/32*exp(a*n*(-1/n^2)^(1/2))*n*x^2*(-1/n^2)^(1/2)/((c*x^n)^(2/3/n))+9/64* n*x^2*(c*x^n)^(2/3/n)*(-1/n^2)^(1/2)/exp(a*n*(-1/n^2)^(1/2))-1/32*n*x^2*(c *x^n)^(2/n)*(-1/n^2)^(1/2)/exp(3*a*n*(-1/n^2)^(1/2))+1/8*exp(3*a*n*(-1/n^2 )^(1/2))*n*x^2*ln(x)*(-1/n^2)^(1/2)/((c*x^n)^(2/n))
\[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx \]
Time = 0.35 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.82, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {4996, 4992, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx\) |
\(\Big \downarrow \) 4996 |
\(\displaystyle \frac {x^2 \left (c x^n\right )^{-2/n} \int \left (c x^n\right )^{\frac {2}{n}-1} \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right )d\left (c x^n\right )}{n}\) |
\(\Big \downarrow \) 4992 |
\(\displaystyle \frac {1}{8} \sqrt {-\frac {1}{n^2}} x^2 \left (c x^n\right )^{-2/n} \int \left (-3 e^{a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\frac {4}{3 n}-1}+3 e^{-a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\frac {8}{3 n}-1}-e^{-3 a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\frac {4}{n}-1}+\frac {e^{3 a \sqrt {-\frac {1}{n^2}} n} x^{-n}}{c}\right )d\left (c x^n\right )\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {1}{8} \sqrt {-\frac {1}{n^2}} x^2 \left (c x^n\right )^{-2/n} \left (-\frac {9}{4} n e^{a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\left .\frac {4}{3}\right /n}+\frac {9}{8} n e^{-a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{\left .\frac {8}{3}\right /n}-\frac {1}{4} n e^{-3 a \sqrt {-\frac {1}{n^2}} n} \left (c x^n\right )^{4/n}+e^{3 a \sqrt {-\frac {1}{n^2}} n} \log \left (c x^n\right )\right )\) |
(Sqrt[-n^(-2)]*x^2*((-9*E^(a*Sqrt[-n^(-2)]*n)*n*(c*x^n)^(4/(3*n)))/4 + (9* n*(c*x^n)^(8/(3*n)))/(8*E^(a*Sqrt[-n^(-2)]*n)) - (n*(c*x^n)^(4/n))/(4*E^(3 *a*Sqrt[-n^(-2)]*n)) + E^(3*a*Sqrt[-n^(-2)]*n)*Log[c*x^n]))/(8*(c*x^n)^(2/ n))
3.1.42.3.1 Defintions of rubi rules used
Int[((e_.)*(x_))^(m_.)*Sin[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Simp[(m + 1)^p/(2^p*b^p*d^p*p^p) Int[ExpandIntegrand[(e*x)^m*(E^(a*b*d ^2*(p/(m + 1)))/x^((m + 1)/p) - x^((m + 1)/p)/E^(a*b*d^2*(p/(m + 1))))^p, x ], x], x] /; FreeQ[{a, b, d, e, m}, x] && IGtQ[p, 0] && EqQ[b^2*d^2*p^2 + ( m + 1)^2, 0]
Int[((e_.)*(x_))^(m_.)*Sin[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_ .), x_Symbol] :> Simp[(e*x)^(m + 1)/(e*n*(c*x^n)^((m + 1)/n)) Subst[Int[x ^((m + 1)/n - 1)*Sin[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])
\[\int x {\sin \left (a +\frac {2 \ln \left (c \,x^{n}\right ) \sqrt {-\frac {1}{n^{2}}}}{3}\right )}^{3}d x\]
Result contains complex when optimal does not.
Time = 0.24 (sec) , antiderivative size = 84, normalized size of antiderivative = 0.47 \[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\frac {1}{64} \, {\left (-2 i \, x^{4} + 9 i \, x^{\frac {8}{3}} e^{\left (\frac {2 \, {\left (3 i \, a n - 2 \, \log \left (c\right )\right )}}{3 \, n}\right )} - 18 i \, x^{\frac {4}{3}} e^{\left (\frac {4 \, {\left (3 i \, a n - 2 \, \log \left (c\right )\right )}}{3 \, n}\right )} + 24 i \, e^{\left (\frac {2 \, {\left (3 i \, a n - 2 \, \log \left (c\right )\right )}}{n}\right )} \log \left (x^{\frac {1}{3}}\right )\right )} e^{\left (-\frac {3 i \, a n - 2 \, \log \left (c\right )}{n}\right )} \]
1/64*(-2*I*x^4 + 9*I*x^(8/3)*e^(2/3*(3*I*a*n - 2*log(c))/n) - 18*I*x^(4/3) *e^(4/3*(3*I*a*n - 2*log(c))/n) + 24*I*e^(2*(3*I*a*n - 2*log(c))/n)*log(x^ (1/3)))*e^(-(3*I*a*n - 2*log(c))/n)
\[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\int x \sin ^{3}{\left (a + \frac {2 \sqrt {- \frac {1}{n^{2}}} \log {\left (c x^{n} \right )}}{3} \right )}\, dx \]
Time = 0.24 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.63 \[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\frac {9 \, c^{\frac {10}{3 \, n}} x^{2} {\left (x^{n}\right )}^{\frac {4}{3 \, n}} \sin \left (a\right ) - 8 \, c^{\frac {2}{3 \, n}} {\left (x^{n}\right )}^{\frac {2}{3 \, n}} \log \left (x\right ) \sin \left (3 \, a\right ) + 18 \, c^{\frac {2}{n}} x^{2} \sin \left (a\right ) - 2 \, c^{\frac {14}{3 \, n}} e^{\left (\frac {2 \, \log \left (x^{n}\right )}{3 \, n} + 4 \, \log \left (x\right )\right )} \sin \left (3 \, a\right )}{64 \, c^{\frac {8}{3 \, n}} {\left (x^{n}\right )}^{\frac {2}{3 \, n}}} \]
1/64*(9*c^(10/3/n)*x^2*(x^n)^(4/3/n)*sin(a) - 8*c^(2/3/n)*(x^n)^(2/3/n)*lo g(x)*sin(3*a) + 18*c^(2/n)*x^2*sin(a) - 2*c^(14/3/n)*e^(2/3*log(x^n)/n + 4 *log(x))*sin(3*a))/(c^(8/3/n)*(x^n)^(2/3/n))
Exception generated. \[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=\text {Exception raised: NotImplementedError} \]
Exception raised: NotImplementedError >> unable to parse Giac output: ((-9 *i)*sageVARn^4*sageVARx^2*exp((-3*i)*sageVARa)*exp((2*sageVARn*abs(sageVAR n)*ln(sageVARx)+2*abs(sageVARn)*ln(sageVARc))/sageVARn^2)+27*i*sageVARn^4* sageVARx^2*exp((-i)
Time = 29.19 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.92 \[ \int x \sin ^3\left (a+\frac {2}{3} \sqrt {-\frac {1}{n^2}} \log \left (c x^n\right )\right ) \, dx=-x^2\,{\mathrm {e}}^{-a\,1{}\mathrm {i}}\,\frac {1}{{\left (c\,x^n\right )}^{\frac {\sqrt {-\frac {1}{n^2}}\,2{}\mathrm {i}}{3}}}\,\left (\frac {9\,n\,\sqrt {-\frac {1}{n^2}}}{128}-\frac {27}{128}{}\mathrm {i}\right )-x^2\,{\mathrm {e}}^{a\,1{}\mathrm {i}}\,{\left (c\,x^n\right )}^{\frac {\sqrt {-\frac {1}{n^2}}\,2{}\mathrm {i}}{3}}\,\left (\frac {9\,n\,\sqrt {-\frac {1}{n^2}}}{128}+\frac {27}{128}{}\mathrm {i}\right )+\frac {x^2\,{\mathrm {e}}^{-a\,3{}\mathrm {i}}\,\frac {1}{{\left (c\,x^n\right )}^{\sqrt {-\frac {1}{n^2}}\,2{}\mathrm {i}}}}{16\,n\,\sqrt {-\frac {1}{n^2}}+16{}\mathrm {i}}+\frac {x^2\,{\mathrm {e}}^{a\,3{}\mathrm {i}}\,{\left (c\,x^n\right )}^{\sqrt {-\frac {1}{n^2}}\,2{}\mathrm {i}}}{16\,n\,\sqrt {-\frac {1}{n^2}}-16{}\mathrm {i}} \]
(x^2*exp(-a*3i)/(c*x^n)^((-1/n^2)^(1/2)*2i))/(16*n*(-1/n^2)^(1/2) + 16i) - x^2*exp(a*1i)*(c*x^n)^(((-1/n^2)^(1/2)*2i)/3)*((9*n*(-1/n^2)^(1/2))/128 + 27i/128) - x^2*exp(-a*1i)/(c*x^n)^(((-1/n^2)^(1/2)*2i)/3)*((9*n*(-1/n^2)^ (1/2))/128 - 27i/128) + (x^2*exp(a*3i)*(c*x^n)^((-1/n^2)^(1/2)*2i))/(16*n* (-1/n^2)^(1/2) - 16i)